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### Can you solve this viral Maths Puzzle? 90% will fail to answer this puzzle question. Only for Geniuses Puzzle with answer!

Find the tactic and solve the puzzle, simple. Solve if you are Genius, check the puzzle image and find which number equals to three. Share your answer through comments.

#### Puzzle Question:

⇒ 8 = 56

⇒ 7 = 42

⇒ 6 = 30

⇒ 5 = 20

⇒ 3 = ??

Options: A) 15,   B) 12,   C) 06

## Math Puzzles Image – Genius Puzzles

Got it? share your answer via comments. Let see what you got! Keep scrolling for the answer. You can also check the video with solution.

Puzzle Video:

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⇒ 8 = 56    ⇒  8 × 7 = 56

⇒ 7 = 42    ⇒  7 × 6 = 42

⇒ 6 = 30    ⇒  6 × 5 = 30

⇒ 5 = 20    ⇒  5 × 4 = 20

⇒ 3 = ??     ⇒  3 × 2 = 6

Answer =  6

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#### 1 COMMENT

1. It turns out the ‘?’ can be whatever we want it to be!

Allow me to illustrate. Take for example, f(x)=(1/40)x^4-(13/20)x^3+(291/40)x^2-(553/20)x+42, and evaluate f(8), f(7), f(6), f(5), f(3). It turns out that:

f(8)=56,
f(7)=42,
f(6)=30,
f(5)=20,
f(3)=9.

Wait, what sorcery is this? Turns out that although the popular rule f(x)=x(x-1), which gives f(x)=6, satisfies the known values in the sequence, that f(x)=(1/40)x^4-(13/20)x^3+(291/40)x^2-(553/20)x+42 also satisfies them–except with a different value of f(3)!

Here’s another one that also works but gives f(3)=12:
f(x)=(1/20)x^4-(13/10)x^3+(271/20)x^2-(543/10)x+84

And here is one where f(3)=π
f(x)=(1/120)(π-6)x^4-(13/60)(π-6)x^3+(1/120)(251π-1386)x^2+(1/60)(3138-533π)x+14(π-6)

Finally, in general if you want the ‘?’=k, i.e., f(3)=k where k is the value of your choice, then
(1/120)(k-6)x^4-(13/60)(k-6)x^3+(1/120)(251k-1386)x^2+(1/60)(3138-533k)x+14(k-6)

More details here: https://www.scribd.com/doc/260182194/Elementary-Sequences
For a non-polynomial rule see here: http://i.imgur.com/BHkg0Ad.png