This post may contain affiliate links. This means if you click on the link and purchase the item, We will receive an affiliate commission at no extra cost to you. See Our Affiliate Policy for more info.

Get ready for a sweet challenge that’s more than just a treat for your taste buds! We present a puzzling scenario involving chocolates, wrappers, and a clever shopkeeper. If you’re a fan of brain teasers and enjoy a good mathematical twist, this one’s for you.

The Chocolate Puzzle: Imagine a world where a shopkeeper sells chocolates for \$1 each. The catch? You can exchange three wrappers for one additional chocolate. Armed with \$15, the question is, how many chocolates can you truly indulge in?

Puzzle Question: A Shopkeeper sells 1 chocolate at \$1 each. You can exchange 3 wrappers for 1 chocolate. If you have \$15, how many chocolates can you totally get?

The Initial Purchase: Starting with \$15, you can purchase 15 chocolates outright. But the fun doesn’t stop there – each chocolate comes with a wrapper, setting the stage for a delightful exchange.

First Round of Exchanges: After enjoying your initial 15 chocolates, you find yourself with 15 wrappers. Exchange these for an extra five chocolates, bringing your total to 20. Now, the plot thickens – with those five new chocolates, you’ve acquired five more wrappers.

The Additional Twist: Here’s where the puzzle takes an unexpected turn. Exchange three of these wrappers for yet another chocolate, leaving you with two wrappers. But wait, there’s more – that extra chocolate means one more wrapper, bringing the count to three.

The Final Exchange: With three wrappers in hand, trade them in for one last chocolate, completing the final round of exchanges.

The Grand Total: Adding it all up: 15 initial chocolates + 5 from the first exchange + 1 from the second exchange + 1 from the third exchange: the grand total is a surprising 22 chocolates!